9.Student Academy - Python Fundamentals / Exercise: Dictionaries - Софтуерен университет

ramioueidat3 0 Точки

9.Student Academy - Python Fundamentals / Exercise: Dictionaries

Write a program that keeps the information about students and their grades.

On the first line, you will receive an integer number representing the next pair of rows. On the next lines, you will receive a student's name and their grade. Keep track of all grades for each student. If the student does not exist, add them.

When you finish reading the data, keep the students with an average grade higher than or equal to 4.50. Order the filtered students by average grade in descending order.

Print the final dictionary with students and their average grade in the following format:

"{name} -> {averageGrade}"

Format the average grade to the 2nd decimal place.

Колеги, отговорите ми излизат правилно, но джъдж ми дава само 12 от 100. Някой може ли да ми каже къде греша? Благодаря предварително!

https://pastebin.com/UzHvnaMW

Тагове:

10/12/2021 14:10:44 Python Fundamentals

icowwww 2813 Точки

Здравей,

Сортировката не ти работи.

Ето една промяна с OrderedDict:

https://pastebin.com/rHSFeezW

10/12/2021 22:00:21 10/12/2021 22:06:05

athristov 32 Точки

Предлагам и моето решение с речник и вложен лист.

n = int(input())
grades_storage = {}

for i in range(n):
    student_name = input()
    student_grade = float(input())

    if student_name not in grades_storage.keys():
        grades_storage[student_name] = []
    grades_storage[student_name].append(student_grade)

for student in grades_storage.keys():
    grades_storage[student] = sum(grades_storage[student]) / len(grades_storage[student])

# grades_storage = {student: grade for student, grade in grades_storage.items() if grade >= 4.50}

for student, grade in grades_storage.items():
    if grade >= 4.50:
        print(f"{student} -> {grade:.2f}")

02/11/2024 21:07:54